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Stoichiometry - Engineering

Q1:

A compound was found having nitrogen and oxygen in the ratio 28 gm and 80 gm respectively. The formula of the compound is

A N2O4

B N2O5

C N2O3

D none of these

ANS:B - N2O5

To determine the formula of the compound, we need to find the simplest whole number ratio of nitrogen to oxygen. Given:

  • Nitrogen mass = 28 g
  • Oxygen mass = 80 g
The atomic mass of nitrogen (N) is approximately 14 g/mol, and the atomic mass of oxygen (O) is approximately 16 g/mol. Now, let's calculate the number of moles of each element:
  • Moles of nitrogen = Nitrogen mass / Atomic mass of nitrogen = 28 g / 14 g/mol = 2 moles
  • Moles of oxygen = Oxygen mass / Atomic mass of oxygen = 80 g / 16 g/mol = 5 moles
The ratio of moles of nitrogen to oxygen is 2:5. To find the empirical formula, we take the simplest whole number ratio. In this case, the simplest ratio is 2:5. So, the empirical formula of the compound is N2O5N2​O5​. Therefore, the correct formula of the compound is N2O5N2​O5​.