A concentrated load acting on the surface of a soil produces a stress of 19.1 kPa at a depth of 1 m below it. Using Boussinesq's expression, the stress at 2 m depth is-A-9.55 kPaB-6.37 kPaC-4.775 kPaD-4.37 kPa-C-4.775 kPa

C 4.775 kPa σ1 = 0.4775 * Q/z1^2 and also right σ2 = 0.4775*Q/z2^2. Take ratio and will get 19.1÷4 = 4.775. σ1 = 19.1, Z1=1, Z2=2, σ2 = ?.