Networks Analysis and Synthesis - Engineering

Q1:

A current 10 sin (200t) A flows through a 5 mH inductance. The expression for voltage is

A 10 sin (200t + 90°)

B 10 sin (200t - 90°)

C 10 sin(1000t + 90°)

D 10 sin (1000t - 90°)

ANS:D - 10 sin (1000t - 90°)

Z = jXL = jωL = = 1∠90° and V = IXL