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Ohm''s Law - Engineering

Q1:

A current of 200 µA through a 6.8 k resistor produces a voltage drop of

A 34.4 V

B 340 V

C 13.6 V

D 1.36 V

ANS:D - 1.36 V

V : I*R.
V : 200*10^-6*6.8*10^3.

V : 200*10^3*6.8.
V : 0.2*6.8.
V : 1.36 VOLTS.