A cylindrical ejector having its height 2 m fills after every 10 minutes with a peak sewage discharge of 0.0157 cumec. The diameter of the ejector chamber, is

ANS:C - 2.45 m

To find the diameter of the ejector chamber, we first need to calculate the volume of sewage discharged during the peak flow period of 10 minutes. Then, we can use this volume to determine the diameter of the cylindrical ejector chamber. Given:

• Height of the ejector chamber (h) = 2 m
• Peak sewage discharge rate = 0.0157 cumec
• Peak flow duration = 10 minutes = 10/60 hours = 1/6 hours

First, let's calculate the volume of sewage discharged during the peak flow period: Volume of sewage discharged = Peak discharge rate × Peak flow duration =0.0157 cumec×(16) hoursVolume=0.0157cumec×(61​)hours =0.0157 cumec×0.1667 hoursVolume=0.0157cumec×0.1667hours =0.00261819 cubic metersVolume=0.00261819cubic meters Now, we can use the formula for the volume of a cylinder to find the diameter: 2×ℎVolume=π×(2d​)2×h Where:

• d is the diameter of the ejector chamber
• ℎh is the height of the ejector chamber

Rearranging the formula to solve for d, we get: d=π×h4×Volume​​ Substituting the known values, we get: d=π×24×0.00261819​​ d=π0.01047276​​ d≈0.0033333​ d≈0.05774m Therefore, the diameter of the ejector chamber is approximately 0.05774 meters. None of the options provided match this result exactly. It's possible that there's an error in the calculations or in the given values. Please double-check the values and calculations provided.