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UPSC Civil Service Exam Questions

Q1:

A cylindrical shell made of mild steel plate of 100 cm diameter is to be subjected to an internal pressure of 10 kg/cm2. If the material yields at 2000 kg/cm2, assuming factor of safety as four and using maximum principal stress theory, thickness of the plate will be

A 5 mm

B 10 mm

C 15 mm

D 20 mm

ANS:B - 10 mm

According to max principal stress theory.
Yield stress = applied stress * f.o.s.

In above problem, applied stress is a hoop stress type and it is equal to (pd/2t).
So,
2000=pd/2t * f.o.s.
2000=(10 * 100/2 * t) * 4.
t = 1cm = 10mm.



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