A deep cut of 7 m has to be made in a clay with unit weight 16 kN/m3 and a cohesion of 25 kN/m2. What will be the factor of safety if one has to have a slope angle of 30° ? Stability number is given to be 0.178 (from Taylor's chart) for a depth factor of 3.-A-0.80B-1.1C-1.25D-1.0-C-1.25

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A deep cut of 7 m has to be made in a clay with unit weight 16 kN/m3 and a cohesion of 25 kN/m2. What will be the factor of safety if one has to have a slope angle of 30&deg; ? Stability number is given to be 0.178 (from Taylor&#39;s chart) for a depth factor of 3.-A-0.80B-1.1C-1.25D-1.0-C-1.25

APTITUDE CRACK · Accepted Answer

C 1.25 FOS = Cu/(&gamma;*Ns*h). = 25/(16*0.178*7). = 1.25.

GATE Exam Questions - Engineering

A deep cut of 7 m has to be made in a clay with unit weight 16 kN/m³ and a cohesion of 25 kN/m². What will be the factor of safety if one has to have a slope angle of 30° ? Stability number is given to be 0.178 (from Taylor's chart) for a depth factor of 3.

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GATE Exam Questions - Engineering

A deep cut of 7 m has to be made in a clay with unit weight 16 kN/m3 and a cohesion of 25 kN/m2. What will be the factor of safety if one has to have a slope angle of 30° ? Stability number is given to be 0.178 (from Taylor's chart) for a depth factor of 3.

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A deep cut of 7 m has to be made in a clay with unit weight 16 kN/m³ and a cohesion of 25 kN/m². What will be the factor of safety if one has to have a slope angle of 30° ? Stability number is given to be 0.178 (from Taylor's chart) for a depth factor of 3.

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