A direct shear test was conducted on a cohesionless soil (c = 0) specimen under a normal stress of 200 kN/m2. The specimen failed at a shear stress of 100 kN/m2. The angle of internal friction of the soil (degrees) is-A-26.6B-29.5C-30.0D-32.6-A-26.6

Question

APTITUDE CRACK · Accepted Answer

A 26.6 Shear stress = C + normal stress*tan (theta). Here given C=0, shear stress = 100 and normal stress = 200. After putting all these values in above formula we will get. theta= 26.56 .

GATE Exam Questions - Engineering

A direct shear test was conducted on a cohesionless soil (c = 0) specimen under a normal stress of 200 kN/m². The specimen failed at a shear stress of 100 kN/m². The angle of internal friction of the soil (degrees) is

For help Students Orientation
Mcqs Questions

Quick Links

Newsletter

GATE Exam Questions - Engineering

A direct shear test was conducted on a cohesionless soil (c = 0) specimen under a normal stress of 200 kN/m2. The specimen failed at a shear stress of 100 kN/m2. The angle of internal friction of the soil (degrees) is

Solution

For help Students Orientation Mcqs Questions

A direct shear test was conducted on a cohesionless soil (c = 0) specimen under a normal stress of 200 kN/m². The specimen failed at a shear stress of 100 kN/m². The angle of internal friction of the soil (degrees) is

For help Students Orientation
Mcqs Questions