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Highway Engineering

Q1: A district road with a bituminous pavement has a horizontal curve of 1000 m for a design speed of 75 km ph. The super-elevation is

A 1 in 40

B 1 in 50

C 1 in 60

D 1 in 70

E none of these.

ANS:A - 1 in 40

Concept:

The superelevation is given by:

e = (V ^ 2)/(225R) Where,
V = speed (in kmph), and R = Radius (in m).

Calculation:

Given: V = 75 kmph, and R = 1000m,
e = ((75) ^ 2)/(225 * 1000) = 1/40.

So, the super elevation is 1/40.



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