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Surveying - Engineering

Q1:

A dumpy level was set up at the midpoint between two pegs A and B, 50 m apart and the staff readings at A and B were 1.22 and 1.06. With the level set up a A, the readings at A and B were 1.55 and 1.37. The collimation error per 100 m length of sight is

A 0.02 m inclined upwards

B 0.04 m inclined downwards

C 0.04 m inclined upward

D none of these.

ANS:B - 0.04 m inclined downwards


The 1st setting is a two peg test which eliminates error thus giving true difference in level.
We usually divide by two when the instrument is not at mid point so that errors on both BS and FS are eliminated. This is the formula to be used in reciprocal levelling. Here the staff is kept at the centre first so the true difference between the elevations is the actual difference between them. True level difference get when the level set midway between A & B.

True level difference=1.22-1.06=.16 downward (Greater value give lower elevation so A is lower elevation than B).

And when an instrument set near to a point collimation error eliminate.So we get true reading for A.
True reading at A=1.55.
When instrument set near A then true reading at B=1.55-.16=1.39.
Error=1.37-1.39=-.02.
Error for 50 m=-0.02.
Error for 100 m=2*(-.02)=-0.04. Here when you put level at centre all errors are eliminated .

Hence difference in RL is 1.22 - 1.06 is 0.16 but the observed staff difference is 1.55 - 1.37 = 0.180.

Therefore the error is 0.180 - 0.160 = 0.02 for 50 m, for 100m it is 0.04. It is positive value hence line of sight is upwards. Distance between a and b = 50 m.
When instrument at center=1.22 - 1.06 = .160.
When instrument near A = 1.55-1.37 = .180.
DIFF = .160-.180 = -.020(- INDICATE DOWNWARDS).

COLLIMATION ERROR FOR 100M length = (.020/50)*100 = .04m inclined downward.