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Stoichiometry - Engineering

Q1:

A gas occupies a volume of 283 c.c at 10°C. If it is heated to 20°C at constant pressure, the new volume of the gas will be __________ c.c.

A 283

B 566

C 293

D 141.5

ANS:C - 293

To solve this problem, we can use Charles's Law, which states that the volume of a gas is directly proportional to its temperature at constant pressure. Mathematically, it's expressed as: 𝑉1𝑇1=𝑉2𝑇2T1​V1​​=T2​V2​​ Where:

  • 𝑉1V1​ is the initial volume of the gas
  • 𝑇1T1​ is the initial temperature of the gas
  • 𝑉2V2​ is the final volume of the gas
  • 𝑇2T2​ is the final temperature of the gas
Given:
  • 𝑉1=283V1​=283 c.c.
  • 𝑇1=10∘C=10+273=283 KT1​=10∘C=10+273=283 K
  • 𝑇2=20∘C=20+273=293 KT2​=20∘C=20+273=293 K (since temperatures must be in Kelvin for this calculation)
We can rearrange the equation to solve for 𝑉2V2​: 𝑉2=𝑉1×𝑇2𝑇1V2​=T1​V1​×T2​​ 𝑉2=283×293283V2​=283283×293​ 𝑉2=293 c.c.V2​=293c.c. So, the new volume of the gas at 20°C will be 293 c.c.293c.c.. Therefore, the correct answer is 293 c.c.