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Analog Electronics - Engineering

Q1:

A generator with an internal resistance of 600 Ω drives an amplifier whose input resistance is 400 Ω. The generator's open circuit voltages is 1 mV; the amplifier develops 100mV across an 8kΩ load. The current amplification is

A 2.5

B 12.5

C 25

D 125

ANS:B - 12.5

Current amplification Av = output current / input current.
Output current -> 100mv/8kohm - 12.5microamp.
Input current -> 1mv/1kohm - 1microamp.

Hence c/t amplification is 12.5.