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Applied Mechanics

Q1:

A load of 500 kg was lifted through a distance of 13 cm. by an effort of 25 kg which moved through a distance of 650 cm. The mechanical advantage of the lifting machine is

A 15

B 18

C 20

D 26

ANS:C - 20

Mechanical Advantage (MA) = Load(W)/Effort(P).
MA = W/P,
= 500/25,
= 20.
So, Option C.



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