Chemical Engineering Basics

Q1: A metal having a Poisson's ratio = 0.3 is elastically deformed under uniaxial tension. If the longitudinal strain = 0.8, then the magnitude of thickness strain is

A -0.8

B 0.8

C +0.08

D -0.24

ANS:D - -0.24

The Poisson's ratio (ν) relates the lateral strain (εlateral​) to the longitudinal strain (εlongitudinal​) in a material under uniaxial tension. It is given by the formula: ν=−​εlateral​​/εlongitudina Given that the Poisson's ratio (ν) is 0.3 and the longitudinal strain (longitudinal​) is 0.8, we can use the formula to find the lateral strain (εlateral​): 0.3=−0.8εlateral​​ εlateral​=−0.3×0.8 εlateral​=−0.24 Therefore, the magnitude of the thickness strain is -0.24. So, the correct option is: −0.24



img not found
img

For help Students Orientation
Mcqs Questions

One stop destination for examination, preparation, recruitment, and more. Specially designed online test to solve all your preparation worries. Go wherever you want to and practice whenever you want, using the online test platform.