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Q1: A noiseless 3 KHz channel can transmit binary at the rate __________ .

A 12000 bps

B 10000 bps

C 6000 bps

D 3000 bps

ANS:C - 6000 bps

Maximum data rate for noiseless channel is given by Nyquist Theorem = 2H log2 V bits/sec V - discrete levels (Here Binary i.e. 2) H - Bandwidth ∴ Maximum data rate = 2H log2 V = 2(3 KHz) log2 2 = 2 x 3 x 103 x 1 = 6 x 103 = 6000 bps.



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