A-P type material has an acceptor ion concentration of 1 x 1016 per cm3. Its intrinsic carrier concentration is 1.48 x 1010/ cm. The hole and electron mobilities are 0.05m2/V-sec and 0.13 m2/V-sec respectively calculate the resistivity of the material-A-12.5 Ω cmB-1.25 Ω cmC-0.125 Ω cmD-125 Ω cm-B-1.25 Ω cm

Question

A-P type material has an acceptor ion concentration of 1 x 1016 per cm3. Its intrinsic carrier concentration is 1.48 x 1010/ cm. The hole and electron mobilities are 0.05m2/V-sec and 0.13 m2/V-sec respectively calculate the resistivity of the material-A-12.5 &Omega; cmB-1.25 &Omega; cmC-0.125 &Omega; cmD-125 &Omega; cm-B-1.25 &Omega; cm

APTITUDE CRACK · Accepted Answer

B 1.25 &Omega; cm 1/&sigma;. 1/e(A+B). A=acceptor concentration x hole mobility. B=carrier concentration x electron mobility. Note: units should be consistent (cm).

Electronic Devices and Circuits

A-P type material has an acceptor ion concentration of 1 x 10¹⁶ per cm³. Its intrinsic carrier concentration is 1.48 x 10¹⁰/ cm. The hole and electron mobilities are 0.05m²/V-sec and 0.13 m²/V-sec respectively calculate the resistivity of the material

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Electronic Devices and Circuits

A-P type material has an acceptor ion concentration of 1 x 1016 per cm3. Its intrinsic carrier concentration is 1.48 x 1010/ cm. The hole and electron mobilities are 0.05m2/V-sec and 0.13 m2/V-sec respectively calculate the resistivity of the material

Solution

For help Students Orientation Mcqs Questions

A-P type material has an acceptor ion concentration of 1 x 10¹⁶ per cm³. Its intrinsic carrier concentration is 1.48 x 10¹⁰/ cm. The hole and electron mobilities are 0.05m²/V-sec and 0.13 m²/V-sec respectively calculate the resistivity of the material

For help Students Orientation
Mcqs Questions