A particle moves with simple harmonic motion. If its acceleration at distance 'D' from the equilibrium position is 'A' then the period of the motion is given by-A-2πADB-C-D--D-

D Answer is D. T = 2pi/w. w = Angular velocity. Now, A = w^2*d. w = [A/d]^1/2. T = 2pi[d/A]^1/2.