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Alternating Current and Voltage

Q1:

A peak current of 12.5 mA is equivalent to ___.

A an rms value of 25 mA

B an average value of 12.5 mA

C a peak-to-peak value of 6.25 mA

D an average value of 7.96 mA

ANS:D - an average value of 7.96 mA

Iav = 2Im/pi.

Im = (pi/2)Iav.

Im = 1.57Iav.



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