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Digital Concepts

Q1:

A periodic digital waveform has a pulse width (tw) of 6 ms and a period (T) of 18 ms. The duty cycle is ________.

A 3.3%

B 33.3%

C 6%

D 18%

ANS:B - 33.3%

D = T/P*100 %.

Where D is the duty cycle, T is the time the signal is active, and P is the total period of the signal.

D = 6ms/18ms*100 {where milli = 10^-3}.

So, D = (6x10^-3)/(18x10^-3)*100.

= (6/18)*(10^-3/10^-3)*100.
= 1/3*100.
= 33.3% HP.



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