A pile is being driven with a drop hammer weighing 1800 kg and having a free fall of 1.00 m. If the penetration with last blow is 5 mm, the load carrying capacity of the pile, -according to the Engineering News formula, is

ANS:D - 10 tonnes

Engineering news formula:-
Qu=WH/6(S+C).

W= 1800kg,
H= 1m (100cm).
S= 5mm (0.5cm)
C=2.5cm(drop hammer).

Qu = 1800*100/6(0.5+2.5).
Qu = 10000kg.
Qu = 10 tonnes. Using the formula WH/S+C*FOS.
So,
C=5mm it is taken in cm = 50cm.

For Drop hammer number of blows = 5.
Given Data
W=1800 , C= 50cm , H= 1m, S= 5blows

Solution:
1800*1/50+5*6 = 1800/180 = 10 tonnes => Answer.