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UPSC Civil Service Exam Questions - Engineering

Q1:

A plan of an area drawn with the original scale of 1 cm = 10 m, has shrunk such that a line, originally 15 cm long on the plan, measures now 14.5 cm. The shrunk scale is given by 1 cm equal to

A 0.97 m

B 9.70 m

C 10.34 m

D 10.97 m

ANS:C - 10.34 m

Shrunk scale = original length * shrunk factor.
Shrunk factor = shrunk length/original length = 14.5/15.
Now Shrunk sclae = 15 * 14.5/100 = 1034.48cm.
= 1034.48/100 = 10.34m.