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Exam Questions Papers - Engineering

Q1:

A point charge of 6 μC is located at the origin, uniform line charge density of 180 nC/m of 8 m length lies along the x axis and a uniform sheet of charge equal to 25 nC/m2 of area p x 42 lies in the z = 0 plane. Calculate total electric flux leaving the surface of sphere of 4 m radius centered at origin.

A 86.97 μC

B 8.697 nC

C 8.697 μC

D 86.97 nC

ANS:C - 8.697 μC

According to Gauss's law total flux leaving the closed surface is equal to the charge enclosed by the closed surface Qencl = (6 x 10-6) + (8 x 180 x 10-6) + (p x 42 x 25 x 10-9) = (6 x 10-6) + (1.44 x 10-6) + (1.257 x 10-6) = 8.697 μ Coulombs.