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RCC Structures Design

Q1: A reinforced concrete cantilever beam is 3.6 m long, 25 cm wide and has its lever arm 40 cm. It carries a load of 1200 kg at its free end and vertical stirrups can carry 1800 kg. Assuming concrete to carry one-third of the diagonal tension and ignoring the weight of the beam, the number of shear stirrups required, is

A 30

B 35

C 40

D 45

E 50

ANS:C - 40

Min spacing criteria are 1)7.5d, 2)300 we use a min of above.
Here the diameter of stirrups which is 6mm min so 6 x 7.5 =45 #so spacing we conveniently take 40. Clear Spacing from either sides of the beam is L/4, i.e, 360/4 = 90 mm.
Now, No. Of Stirrups = L/ spacing = 3600/90 = 40.
The answer is C.



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