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GATE Exam Questions - Engineering

Q1:

A road is provided with a horizontal circular curve having deflection angle of 55° and centre line radius of 250 m. A transition curve is to be provided at each end of the circular curve of such a length that the rate of gain of radial acceleration is 0.3 m/s3 at a speed of 50 km per hour. Length of the transition curve required at each of the ends is

A 2.57 m

B 33.33 m

C 35.73 m

D 16666.67 m

ANS:C - 35.73 m

V=(5/18)*50 = 13.89m/s.

Formula:
L = v^3/(c*R).

Here, c = o.3 m/s.
v = 13.88888888 m/s.
R = 250.

Hence, L = 13.88888888^3/(0.3*250).
= 35.73.