A round steel bar of overall length 40 cm consists of two equal portions of 29 cm each having diameters of 10 cm and 8 cm respectively. If the rod is subjected to a tensile load of 10 tones, the elongation will be given by :(E = 2 x 106 kg/cm2)-A-1/10π (1/25 + 1/16) cmB-2/10π (1/25 + 1/16) cmC-3/10 π (1/25 + 1/16) cmD-4/10 π (1/25 + 1/16) cm-A-1/10π (1/25 + 1/16) cm

Question

A round steel bar of overall length 40 cm consists of two equal portions of 29 cm each having diameters of 10 cm and 8 cm respectively. If the rod is subjected to a tensile load of 10 tones, the elongation will be given by :(E = 2 x 106 kg/cm2)-A-1/10&pi; (1/25 + 1/16) cmB-2/10&pi; (1/25 + 1/16) cmC-3/10 &pi; (1/25 + 1/16) cmD-4/10 &pi; (1/25 + 1/16) cm-A-1/10&pi; (1/25 + 1/16) cm

APTITUDE CRACK · Accepted Answer

A 1/10&pi; (1/25 + 1/16) cm No, the equal portions will be 20 cm each.

UPSC Civil Service Exam Questions - Engineering

A round steel bar of overall length 40 cm consists of two equal portions of 29 cm each having diameters of 10 cm and 8 cm respectively. If the rod is subjected to a tensile load of 10 tones, the elongation will be given by :(E = 2 x 10⁶ kg/cm²)

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UPSC Civil Service Exam Questions - Engineering

A round steel bar of overall length 40 cm consists of two equal portions of 29 cm each having diameters of 10 cm and 8 cm respectively. If the rod is subjected to a tensile load of 10 tones, the elongation will be given by :(E = 2 x 106 kg/cm2)

Solution

For help Students Orientation Mcqs Questions

A round steel bar of overall length 40 cm consists of two equal portions of 29 cm each having diameters of 10 cm and 8 cm respectively. If the rod is subjected to a tensile load of 10 tones, the elongation will be given by :(E = 2 x 10⁶ kg/cm²)

For help Students Orientation
Mcqs Questions