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Applied Mechanics

Q1:

A Second's pendulum gains 2 minutes a day. To make it to keep correct time its length

A must be decreased

B must be increased

C is not changed but weight of the bob is increased

D is not changed but weight of the bob is decreased

E none of these.

ANS:B - must be increased

T=2π*[(squareroot of l/g)].

Hence time period of second pendulum is directly proportional to square root of its length.



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