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Series Circuits - Engineering

Q1:

A series circuit has a 24 V source and a total resistance of 120 . The current through each resistor is

A 24 mA

B 200 mA

C 120 mA

D 20 mA

ANS:B - 200 mA

I = V/R, we get answer as 0.2 ohms.

But we want to answer in terms of mA so, converting Ohms into mA.

I =0.2 Ohms= 2*(10^-1)*(10^-2)*(10^2) =2*(10^2) mA = 200 mA.