- Networks Analysis and Synthesis - Section 1
- Networks Analysis and Synthesis - Section 2
- Networks Analysis and Synthesis - Section 3
- Networks Analysis and Synthesis - Section 4
- Networks Analysis and Synthesis - Section 5
- Networks Analysis and Synthesis - Section 6
- Networks Analysis and Synthesis - Section 7
- Networks Analysis and Synthesis - Section 8
- Networks Analysis and Synthesis - Section 9
- Networks Analysis and Synthesis - Section 10
- Networks Analysis and Synthesis - Section 11
- Networks Analysis and Synthesis - Section 12
- Networks Analysis and Synthesis - Section 13
- Networks Analysis and Synthesis - Section 14
- Networks Analysis and Synthesis - Section 15
- Networks Analysis and Synthesis - Section 16
- Networks Analysis and Synthesis - Section 17
- Networks Analysis and Synthesis - Section 18
- Networks Analysis and Synthesis - Section 19
- Networks Analysis and Synthesis - Section 20
- Networks Analysis and Synthesis - Section 21
- Networks Analysis and Synthesis - Section 22
- Networks Analysis and Synthesis - Section 23
- Networks Analysis and Synthesis - Section 24
- Networks Analysis and Synthesis - Section 25
- Networks Analysis and Synthesis - Section 26
- Networks Analysis and Synthesis - Section 27
 
             
            Networks Analysis and Synthesis - Engineering
| Q1: A series RC circuit has R = 5 Ω and C = 10 μF. The current in the circuit is 5 sin 20000t. The applied voltage isA 
 252 sin (20000t + 45°) B 
 252 sin (20000t - 45°) C 
 252 sin 20000t D 
 252 sin (20000t - 90°) ANS:B - 252 sin (20000t - 45°)    Z = R2 + XC2 = 50
V = 550 sin(20000 t - 45°)
V = 252 sin(20000 t - 45°) | 
 
             
                            
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