- Waste Water Engineering - Section 1
- Waste Water Engineering - Section 2
- Waste Water Engineering - Section 3
- Waste Water Engineering - Section 4
- Waste Water Engineering - Section 5
- Waste Water Engineering - Section 6
- Waste Water Engineering - Section 7


Waste Water Engineering - Engineering
Q1: A sewer pipe contains 1 mm sand particles of specific gravity 2.65 and 5 mm organic particles of specific gravity 1.2, the minimum velocity required for removing the sewerage, isA
0.30 m/sec
B
0.35 m/sec
C
0.40 m/sec
D
0.45 m/sec
E
0.50 m/sec
ANS:D - 0.45 m/sec To determine the minimum velocity required for removing the sewerage (i.e., preventing sedimentation and buildup) in the sewer pipe, we need to calculate the critical velocity for both types of particles separately and then take the maximum of the two critical velocities. The critical velocity for particles is given by the formula: Vc= Gravity×(Specific Gravityparticle−Specific Gravityfluid)×Particle Size / 18×Viscosity Given:
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