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UPSC Civil Service Exam Questions - Engineering

Q1:

A simply supported beam of span 'L' and uniform flexural rigidly EI, carries a central load 'W' and total uniformly distributed load 'W' throughout the span. The maximum deflection is given by

A 13 WL3/96 EI

B 5 WL3/384 EI

C 5 WL3/96 EI

D 13 WL3/384 EI

ANS:D - 13 WL3/384 EI

Max. Deflection due to a concentrated load at the centre
=WL^3/48EI.

Max. Deflection due to total uniformly distributed load W =5WL^3/384EI.

Total MAX. DEFLECTION= WL^3/48EI+WL^3/384EI=13WL^3/384EI.