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Alternating Current and Voltage - Engineering

Q1:

A sinusoidal current has an rms value of 14 mA. The peak-to-peak value is

A 45.12 mA

B 16 mA

C 39.6 mA

D 22.6 mA

ANS:C - 39.6 mA

GIVEN:

Irms = 14 m, Irms (p-p) = 14*2 = 28 m.

We have:

I(p-p) = Irms (p-p)*squreroot of 2 or 1.41.
I(p-p) = 28 m*1.41.
I(p-p) = 39.6.