Theory of Structures - Engineering

Q1:

A steel bar 5 m x 50 mm is loaded with 250, 000 N. If the modulus of elasticity of the material is 0.2 MN/mm2 and Poisson's ratio is 0.25, the change in the volume of the bar is :

A 1.125 cm3

B 2.125 cm3

C 3.125 cm3

D 4.125 cm2

ANS:C - 3.125 cm3

@ALL.

hERE a steel bar 5m length and 50mm dia...then the original volume will be Pid2/4 multiply length = .01m3.

Now change in volume = 25000÷( .002 * .2 *10^6) multiply (1-2*.25).01 = 3.125cm3.