A steel rod of sectional area 250 sq. mm connects two parallel walls 5 m apart. The nuts at the ends were tightened when the rod was heated to 100°C. If αsteel = 0.000012/C°, Esteel = 0.2 MN/mm2, the tensile force developed at a temperature of 50°C, is-A-80 N/mm2B-100 N/mm2C-120 N/mm2D-150 N/mm2-C-120 N/mm2

Question

A steel rod of sectional area 250 sq. mm connects two parallel walls 5 m apart. The nuts at the ends were tightened when the rod was heated to 100&deg;C. If &alpha;steel = 0.000012/C&deg;, Esteel = 0.2 MN/mm2, the tensile force developed at a temperature of 50&deg;C, is-A-80 N/mm2B-100 N/mm2C-120 N/mm2D-150 N/mm2-C-120 N/mm2

APTITUDE CRACK · Accepted Answer

The correct option is  C 120 N/mm2 Stress = Eat =0.2*10^6 *0.000012 * 50 = 120N/mm^2.

Theory of Structures

Q1: A steel rod of sectional area 250 sq. mm connects two parallel walls 5 m apart. The nuts at the ends were tightened when the rod was heated to 100°C. If α_steel = 0.000012/C°, E_steel = 0.2 MN/mm², the tensile force developed at a temperature of 50°C, is

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Theory of Structures

Q1: A steel rod of sectional area 250 sq. mm connects two parallel walls 5 m apart. The nuts at the ends were tightened when the rod was heated to 100°C. If αsteel = 0.000012/C°, Esteel = 0.2 MN/mm2, the tensile force developed at a temperature of 50°C, is

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Q1: A steel rod of sectional area 250 sq. mm connects two parallel walls 5 m apart. The nuts at the ends were tightened when the rod was heated to 100°C. If α_steel = 0.000012/C°, E_steel = 0.2 MN/mm², the tensile force developed at a temperature of 50°C, is

For help Students Orientation
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