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Applied Mechanics

Q1: A stone of mass 1 kg is tied to a string of length 1 m and whirled in a horizontal circle at a constant angular speed 5 rad/sec. The tension in the string is,

A 5 N

B 10 N

C 15 N

D 25 N

E None of these.

ANS:D - 25 N

Given:

  • Mass of the stone, M=1kg
  • Angular speed, W=5rad/sec
  • Length of the string, r= 1 m
The linear speed of the stone is given by: v=r⋅ω Substitute the values: V=(1 m)⋅(5 rad/sec)=5 m/sec Now, the tension (T) in the string provides the centripetal force needed to keep the stone moving in a circle. Therefore, we have: T=m⋅acceleration​ Therefore, the tension in the string is 25 N25N.



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