A string of length 90 cm is fastened to two points A and B at the same level 60 cm apart. A ring weighing 120 g is slided on the string. A horizontal force P is applied to the ring such that it is in equilibrium vertically below B. The value of P is :-A-40 gB-60 gC-80 gD-100 g-C-80 g

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APTITUDE CRACK · Accepted Answer

C 80 g Taking Moments at point B. M1 * d1 = M2 * d2 m1 = 120g, d1 = 60cm d2 = 90cm. Lengh of string. Hence subtitute 120g * 60cm = m2 * 90. By solving m2 = 120 * 60/90 = &gt; m = 80g. Correct answer.

Applied Mechanics - Engineering

A string of length 90 cm is fastened to two points A and B at the same level 60 cm apart. A ring weighing 120 g is slided on the string. A horizontal force P is applied to the ring such that it is in equilibrium vertically below B. The value of P is :

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Applied Mechanics - Engineering

A string of length 90 cm is fastened to two points A and B at the same level 60 cm apart. A ring weighing 120 g is slided on the string. A horizontal force P is applied to the ring such that it is in equilibrium vertically below B. The value of P is :

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For help Students Orientation Mcqs Questions

For help Students Orientation
Mcqs Questions