- Networks Analysis and Synthesis - Section 1
- Networks Analysis and Synthesis - Section 2
- Networks Analysis and Synthesis - Section 3
- Networks Analysis and Synthesis - Section 4
- Networks Analysis and Synthesis - Section 5
- Networks Analysis and Synthesis - Section 6
- Networks Analysis and Synthesis - Section 7
- Networks Analysis and Synthesis - Section 8
- Networks Analysis and Synthesis - Section 9
- Networks Analysis and Synthesis - Section 10
- Networks Analysis and Synthesis - Section 11
- Networks Analysis and Synthesis - Section 12
- Networks Analysis and Synthesis - Section 13
- Networks Analysis and Synthesis - Section 14
- Networks Analysis and Synthesis - Section 15
- Networks Analysis and Synthesis - Section 16
- Networks Analysis and Synthesis - Section 17
- Networks Analysis and Synthesis - Section 18
- Networks Analysis and Synthesis - Section 19
- Networks Analysis and Synthesis - Section 20
- Networks Analysis and Synthesis - Section 21
- Networks Analysis and Synthesis - Section 22
- Networks Analysis and Synthesis - Section 23
- Networks Analysis and Synthesis - Section 24
- Networks Analysis and Synthesis - Section 25
- Networks Analysis and Synthesis - Section 26
- Networks Analysis and Synthesis - Section 27
Networks Analysis and Synthesis - Engineering
Q1:
 . The system is at rest for t < 0, i(t) = 2u(t) where u(t) is an unit step, V(t) for t > 0 is given by |
V(t) = 2e-6t.
