Networks Analysis and Synthesis

Q1: A thermal power plant has an efficiency of 0.4. If 0.6 kg of coal is burnt to generate 1 kWh, the calorific value of coal is

A about 3500 kcal/kg

B about 2500 kcal/kg

C about 1500 kcal/kg

D about 7500 kcal/kg

ANS:A - about 3500 kcal/kg

Therefore, calorific value =



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