A torsion member is fabricated from two concentric thin tubes. At the ends, the tubes are welded to rigid discs so that both the tubes are twisted as a unit. The radius of the outer tube is 2r and that of the inner tube is r. If the shear stresses developed in the outer tube is τ, then the shear stress in the inner tube will be.-A-τB-0.25 τC-0.75 τD-0.5 τ-D-0.5 τ

Question

A torsion member is fabricated from two concentric thin tubes. At the ends, the tubes are welded to rigid discs so that both the tubes are twisted as a unit. The radius of the outer tube is 2r and that of the inner tube is r. If the shear stresses developed in the outer tube is &tau;, then the shear stress in the inner tube will be.-A-&tau;B-0.25 &tau;C-0.75 &tau;D-0.5 &tau;-D-0.5 &tau;

APTITUDE CRACK · Accepted Answer

The correct option is  D 0.5 &tau; T/J = &pound;/r. Take &pound; is directly proportional to r.

UPSC Civil Service Exam Questions

For help Students Orientation
Mcqs Questions

Quick Links

Newsletter

UPSC Civil Service Exam Questions

Solution

For help Students Orientation Mcqs Questions

For help Students Orientation
Mcqs Questions