Q1: A train is hauled by 2-8-2 locomotive with 22.5 tonnes load on each driving axle. Assuming the coefficient of rail-wheel friction to be 0.25, what would be the hauling capacity of the locomotive ?

ANS:B - 22.5 tonnes

Hauling capacity- f*n*w.

Where f- coefficient of friction
n- no of DRIVING AXLES
W- total load on each axle.

In 2-8-2 locomotive 1st 2 refers to leading wheels , and 8 refers to driving wheels, and 2nd 2 refers to trailing wheels. So no of driving axles are 8/2 = 4.
Hence hauling capacity= 0.25 *4 *22.5.
= 22.5 tonnes.