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Bipolar Junction Transistors (BJT)

Q1:
A transistor has a mca12_1001a1.gif of 250 and a base current, IB, of 20 mu.gif A. The collector current, IC, equals:

A 500 mu.gif A

B 5 mA

C 50 mA

D 5 A

ANS:B - 5 mA

Given datas:bette = 250,current base = 20micro ampere.
Then IC = bette*current base.
IC = 250 * 20 = 5000micro ampere.

Convetion of 5000MA into mA will be 5mA(Ans).



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