Analog Electronics

Q1: A transistor with a = 0.9 and ICBO = 10 μA is biased so that IBQ = 90 μA. Then IEQ will be

A 5.15 mA

B 5.2 mA

C 5 mA

D 990 mA

ANS:D - 990 mA

IEQ = ICQ + IBQ = 910 μA + 90 μA  990 μA.



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