A transistor with a = 0.9 and ICBO = 10 μA is biased so that IBQ = 90 μA. Then ICQ will be-A-910 mAB-5 mAC-5.25 mAD-4.95 mA-A-910 mA

A 910 mA ICEO = (β + 1)ICBO (9 + 1) 10 μA 100 μA ICQ = 9 x 90 x 10 6 + 100 x 10 6 = 910 μA.