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UPSC Civil Service Exam Questions - Engineering

Q1:

A truss is shown in the given figure. The cross-sectional area of each member is 'A' and the modulus of elasticity of the material is E. The strain energy in the member XY is given by

A P2L/2AE

B P2L/QAE

C P2L/3AE

D zero

ANS:D - zero

As we know,

Strain energy for any member (u) = p2l/2ae.
As here is no vertical force in the 'xy' member, so p=0.
So, u=0.