A vacuum parallel plate capacitor is charged. The field between the plates is 2 x 104 V/m. If the space between the plates is filled with a material having ∈r = 10, then the value of field in the dielectric will be-A-2 x 103 V/mB-x 104 V/mC- .root { background image: url(/_files/images/chemical engineering/common/root.gif); background position: top left; background repeat: no repeat; padding left: 10px; padding top: 1px; } 210 x 104 V/mD-2 x 105 V/m-A-2 x 103 V/m

Question

A vacuum parallel plate capacitor is charged. The field between the plates is 2 x 104 V/m. If the space between the plates is filled with a material having &isin;r = 10, then the value of field in the dielectric will be-A-2 x 103 V/mB-x 104 V/mC- .root { background image: url(/_files/images/chemical engineering/common/root.gif); background position: top left; background repeat: no repeat; padding left: 10px; padding top: 1px; } 210 x 104 V/mD-2 x 105 V/m-A-2 x 103 V/m

APTITUDE CRACK · Accepted Answer

The correct option is  A 2 x 103 V/m D &prop; &isin;rE. The flux density is the same. Since &isin;r has become 10 times, E decreases by 10 times.

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Q1: A vacuum parallel plate capacitor is charged. The field between the plates is 2 x 10⁴ V/m. If the space between the plates is filled with a material having ∈_r = 10, then the value of field in the dielectric will be

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Q1: A vacuum parallel plate capacitor is charged. The field between the plates is 2 x 104 V/m. If the space between the plates is filled with a material having ∈r = 10, then the value of field in the dielectric will be

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Q1: A vacuum parallel plate capacitor is charged. The field between the plates is 2 x 10⁴ V/m. If the space between the plates is filled with a material having ∈_r = 10, then the value of field in the dielectric will be

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