A voltage v = 100 sin ωt + 10 sin 5 ωt is applied to a pure capacitor having capacitance of 1 μF. If ω = 314 rad/sec, the current through the capacitor is-A-0.0314 cos 314 t + 0.0157 cos 1570 tB-0.0314 sin 314 t + 0.0157 sin 1570 tC-0.0314 cos 314 t + 0.0314 cos 1570 tD-0.0157 cos 314 t + 0.0157 cos 1570 t-A-0.0314 cos 314 t + 0.0157 cos 1570 t

Question

A voltage v = 100 sin &omega;t + 10 sin 5 &omega;t is applied to a pure capacitor having capacitance of 1 &mu;F. If &omega; = 314 rad/sec, the current through the capacitor is-A-0.0314 cos 314 t + 0.0157 cos 1570 tB-0.0314 sin 314 t + 0.0157 sin 1570 tC-0.0314 cos 314 t + 0.0314 cos 1570 tD-0.0157 cos 314 t + 0.0157 cos 1570 t-A-0.0314 cos 314 t + 0.0157 cos 1570 t

APTITUDE CRACK · Accepted Answer

A 0.0314 cos 314 t + 0.0157 cos 1570 t  For Fundamental .

Signals and Systems - Engineering

A voltage v = 100 sin ωt + 10 sin 5 ωt is applied to a pure capacitor having capacitance of 1 μF. If ω = 314 rad/sec, the current through the capacitor is

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Signals and Systems - Engineering

A voltage v = 100 sin ωt + 10 sin 5 ωt is applied to a pure capacitor having capacitance of 1 μF. If ω = 314 rad/sec, the current through the capacitor is

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