Mechanical Operations

Q1: According to Bond crushing law, the work required to form particle of size 'D' from very large feed is (where (S/V)p and (S/V)f are surface to volume ratio of the product and feed respectively).

A (S/V)p

B (S/V)p

C (S/V)2p

D (S/V)f

ANS:B - (S/V)p

According to Bond's crushing law, the work required to form a particle of size DDD from a very large feed is proportional to the surface to volume ratio of the feed material, denoted as (S/V)f(S/V)_f(S/V)f​. Bond's law states: W=k(S/V)fW = \frac{k}{(S/V)_f}W=(S/V)f​k​ Where:

  • WWW is the work required to form the particle of size DDD.
  • kkk is a constant.
  • (S/V)f(S/V)_f(S/V)f​ is the surface to volume ratio of the feed material.
Therefore, the correct answer is (S/V)f(S/V)_f(S/V)f​.



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