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Mass Transfer - Engineering

Q1:

According to Chilton-Colburn analogy for mass transfer, NSt.NSc2/3 is equal to

A f

B f/2

C 2f

D 1/f

ANS:B - f/2

In the Chilton-Colburn analogy, which relates momentum transfer (fluid flow) and mass transfer (diffusion), the dimensionless groups NSt and NSc are used to represent the Nusselt number for heat transfer and the Sherwood number for mass transfer, respectively. The Chilton-Colburn analogy states that the Sherwood number NSc is related to the Nusselt number NSt by the equation: NSc=NSt×(PrSc)2/3NSc=NSt×(ScPr​)2/3 Where:

  • NSc is the Sherwood number.
  • NSt is the Nusselt number.
  • Pr is the Prandtl number.
  • Sc is the Schmidt number.
Now, to find the relationship between NSc and NSt, we can use the given equation and isolate NSc: NSc=NSt×(PrSc)2/3NSc=NSt×(ScPr​)2/3 Therefore, NSc/NSt is given by: NScNSt=(PrSc)2/3NStNSc​=(ScPr​)2/3 So, NSc/NSt equals (PrSc)2/3(ScPr​)2/3.