Engineering Mechanics - Engineering

Q1:

According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through centre of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.)

A IP = IG + Ah2

B IP = IG - Ah2

C IP = IG / Ah2

D IP = Ah2 / IG

ANS:A - IP = IG + Ah2

Explanation: No answer description is available.