- Chemical Engineering Basics - Section 1
- Chemical Engineering Basics - Section 2
- Chemical Engineering Basics - Section 3
- Chemical Engineering Basics - Section 4
- Chemical Engineering Basics - Section 5
- Chemical Engineering Basics - Section 6
- Chemical Engineering Basics - Section 7
- Chemical Engineering Basics - Section 8
- Chemical Engineering Basics - Section 9
- Chemical Engineering Basics - Section 10
- Chemical Engineering Basics - Section 11
- Chemical Engineering Basics - Section 12
- Chemical Engineering Basics - Section 13
- Chemical Engineering Basics - Section 14
- Chemical Engineering Basics - Section 15
- Chemical Engineering Basics - Section 16
- Chemical Engineering Basics - Section 17
- Chemical Engineering Basics - Section 18
- Chemical Engineering Basics - Section 19
- Chemical Engineering Basics - Section 20
- Chemical Engineering Basics - Section 21
- Chemical Engineering Basics - Section 22
- Chemical Engineering Basics - Section 23
- Chemical Engineering Basics - Section 24
- Chemical Engineering Basics - Section 25
- Chemical Engineering Basics - Section 26
- Chemical Engineering Basics - Section 27
- Chemical Engineering Basics - Section 28


Chemical Engineering Basics - Engineering
Q1: Air/fuel ratio on molar (volume) basis for combustion of methane with theoretical quantity of air with beA 9.5:1
B 12.5:1
C 15.5 :1
D 18.5 : 1
ANS:A - 9.5:1 To determine the air/fuel ratio for the combustion of methane (CH4) with the theoretical quantity of air, we need to consider the stoichiometry of the reaction. The balanced chemical equation for the combustion of methane is: CH4+2O2→CO2+2H2O From the equation, we see that 1 mole of methane reacts with 2 moles of oxygen to produce 1 mole of carbon dioxide and 2 moles of water vapor. Now, for complete combustion, the reaction needs the stoichiometric amount of oxygen. The molar ratio of oxygen to methane is 2:1, which means 2 moles of oxygen are required for every mole of methane. Therefore, the air/fuel ratio on a molar (volume) basis is given by: Air/Fuel Ratio=2:1 So, the correct answer is 12.5:112.5:1. |


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