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Inductors - Engineering

Q1:

An 18 V power supply is connected across a coil with a winding resistance of 180 . Current flow in the coil is

A 1 mA

B 10 mA

C 100 mA

D 1 A

ANS:C - 100 mA

v=ir
so,
i=v/r
by ohms law.

So here we have v=18.
i=?
r=180
then,
i=18/180
=0.1A.

i.e=100mA.